¹¤³ÌÔì¼ÛÊÖ¹¤Ëã¸Ö½îÏÂÁÏ·½·¨¼¼ÇÉ£º

Áº°å¸Ö½îµÄÏÂÁϳ¤¶È=Áº°åµÄÖáÏ߳ߴç-±£»¤²ã(Ò»°ã25)+ÉÏÍä¹´³ß´ç

180¶ÈÍä¹´=6.25d

90¶ÈÍä¹´=3.5d

45¶ÈÍä¹´=4.9d

ÔÙ¼õÈ¥¶ÈÁ¿²î£º30¶Èʱȡ0.3d 45¶È0.5d 60¶È1d 90¶È2d 135¶È3d

Èç¹ûÊÇÒ»°ãµÄÊ©¹¤Í¼Ö½°´ÉÏÃæµÄ·½·¨¾Í¿ÉÒÔËã³öÀ´Èç°åµÄ·Ö²¼½î¸ºÅÌÁºµÄ×ÝÏòÊÜÁ¦½î¼ÜÁ¦½î¡£Èç¹ûÊÇÆ½·¨Ê©¹¤Í¼ÄǾÍÒª²Î¿¼03g101-1BÁË

¹¿½îµÄ³¤¶È£ºÍâ°ü³¤¶È+Íä¹´³¤¶È-6d

Íä¹´³¤¶È6¼Ó1008¼Ó12010¼Ó140

¹¿½î¸öÊý=Áº¹¹¼þ³¤¶È-(25±£»¤²ã)*2/¹¿½î¼ä¾à+1

¾ØÐι¿½îÏÂÁϳ¤¶È¼ÆË㹫ʽ

¹¿½îÏÂÁϳ¤¶È=¹¿½îÖܳ¤+¹¿½îµ÷ÕûÖµ

ʽÖУº

¹¿½îÖܳ¤=2(Íâ°ü¿í¶È+Íâ°ü³¤¶È);

Íâ°ü¿í¶È=b-2c+2d;

Íâ°ü³¤¶È=h-2c+2d;

h=¹¹¼þºá½ØÃæ¿í׸ß;

×ÝÏò¸Ö½îµÄ±£»¤²ãºñ¶È;

¹¿½îÖ±¾¶¡£

¹¤³ÌÔì¼ÛÊÖ¹¤Ëã¸Ö½îÏÂÁÏ·½·¨¼¼ÇÉ£¬Äãѧ»áÁËÂð£¿